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Last two! =) @Mertsj
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I believe the second one is 166.67 =)
2log35 + log32 =log35^2+log32=log35^2(32)=log39200
So how would I type that answer if the form is suppose to be log(basea)b?
\[3^{x+1}=500\] \[(x+1)\log3=\log500\] \[x+1=\frac{\log 500}{\log 3}=5.65678\] x=4.65678
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Thank you sooo much! =)
\[\log_{10}39200 \]
I really appreciate all your help, thank you! =)
yw
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