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find the zeros f(x)=3x^3+2x^2-8x
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factor out an x, and you have a zero at 0, and a quadratic equation x(....) = 0
3x^3+2x^2-8x x(3x^2 + 2x - 8)=0 x((x+2)(3x-4))=0 x=0 x=-2 x=4/3
thanks
yw
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