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Solve 2/(2x+5)+3/(2x-5)=(10x+5)/(4x^2-25)
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\[\frac{2}{(2x+5)}+\frac{3}{(2x-5)}=\frac{(10x+5)}{(4x^2-25)}\]
I got x=5/6
yup , to check it just substitute the x in the equation if the left and right side of the equation are equal therefore you are correct
oh okay, thanks I forgot about doing that...
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