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\[(3/7)^{2x}=49/9\]
you can rewrite the left hand side to be \[7^{2} / 3^{2}\]
Yup! I got that part
\(\Large \color{MidnightBlue}{\Rightarrow {49 \over 9} = {7^2 \over 3^2} = ({3 \over 7})^{-2} }\) Now, let's equate the exponents. \(\Large \color{MidnightBlue}{\Rightarrow -2 = 2x }\) \(\Large \color{MidnightBlue}{\Rightarrow x = -1 }\)
There it is
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What do you use to make your answers look so neat @ParthKohli
haha, I wonder the same!
LaTeX :P
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