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Mathematics 13 Online
OpenStudy (anonymous):

What is the equation of the attached graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

just reflect y=lnx over the x-axis... do you know what to do?

OpenStudy (anonymous):

Is it f(x)= log(x+1)?

OpenStudy (anonymous):

that moves it to the left 1 unit.

OpenStudy (anonymous):

So it would be f(x)= log(x-1)

OpenStudy (anonymous):

what reflects y=x^2 to this?|dw:1337579988996:dw|

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