Question

I'm still confused about logs ><;
solve the following simultaneous equation:

x^{2}y = 125
lg x + 2lg y = 3

so stressed man ;^; so far I got:
x^{2}y = 5^{3}

lg x + lg y^{2} = 3
lg xy^{2} = 3
xy^{2} = 10^{3}


then...... ;A;

Answer 1

log base x of 125