for the function y= 2+3sinx find the amplitude and the max value
The amplitude is 3 and the max value is 5. Do you know why/how?
thats not right according to my solution book
Perhaps your solution book is wrong. I put this directly into wolfram alpha after you tried to tell me it is wrong. http://www.wolframalpha.com/input/?i=y%3D+2%2B3sinx The starting value is of the function is 2, it osciallates around this number, and the max value is the amplitude (3; the coefficient of the sin(x)) plus the starting value of the function.
oh i see
hmmmm.....don't u study the first derivative to find min & max?
@virtus what does your answer book say?
I think my solution is wrong haha
i think chaise is right
Oh, I guess it depends on the way you interpret min and max. I assumed it was the max value of y. Perhaps you are right in saying that Angela.
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