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Mathematics 10 Online
OpenStudy (anonymous):

Find P(X > 2). X 1 2 3 4 P(X) 0.30 0.40 0.15 ?

OpenStudy (unklerhaukus):

∑P(x)=1

OpenStudy (unklerhaukus):

use this to find P(4)

OpenStudy (unklerhaukus):

then add the probabilities of the numbers where x>2

OpenStudy (anonymous):

thanks :)

OpenStudy (unklerhaukus):

what answer did you arrive at?

OpenStudy (unklerhaukus):

Another way i just thought of is to say that \[P(X>2)\]\[=1-P(X<2)\]

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