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What is the x-coordinate of the vertex of this parabola? y = -3x^2+12x-5
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y = -3x² +12x - 5 y = -3(x² + 4x) - 5 y = -3(x² + 4x + 4 - 4) - 5 y = -3(x² + 4x + 4) + 12 - 5 y = -3(x + 2)² + 7 x-coordinate is (-2 , 7)
what is a parabola?
Answer Choices... A.)-3 B.)2 C.)12
is it B)
Thats what im wondering..
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me too....
well, let's see if @HairtUB knows the answer.
^Right
ok=]
Ok wait, yeah it's B. I made a mistake in my calculations. Here's the correct version: y = -3x² +12x - 5 y = -3(x² - 4x) - 5 y = -3(x² - 4x + 4 - 4) - 5 y = -3(x² - 4x + 4) + 12 - 5 y = -3(x - 2)² + 7 coordinate is (-2 , 7) x-coordinate is 2.
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^Thanks
ok, i was right, thank u
you were :D
:D
No prob :) And sorry for the confusion :/
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its okay:)
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