Question

What is the 32nd term of the arithmetic sequence where a1 = -32 and a9 = -120?
Choose one answer.
a. -384
b. -373
c. -362
d. -351

Answer 1

Does anybody know how to do this?

Answer 2

a9 = a1 + 8d = -120
-32 + 8d = -120
8d = -88
d = -11
common difference = -11
32nd term = a1 + 31d
= -32 + 31*-11
= -32 - 341
= -373

Answer 3

Thanks!

Answer 4

ok - i was a bit slow as i was disturbed by an affectionate cat

Answer 5

Haha its ok lol