Question

(-2a^2)^-2
____________
4a^2

Answer 1

\[\frac{(-2a^2)^{-2}}{4a^2}=\frac{\frac{1}{4a^4}}{4a^2}=\frac{1}{16a^6}\]

Answer 2

Did you add a^4 and a^2 to get a^6 at the bottom?

Answer 3

Multiplied, which causes the exponents to be added.