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OpenStudy (anonymous):

verify the identity cos [(pi/2) - x]/sin[(pi/2 - x] = tan x please help!

5 years ago
OpenStudy (callisto):

\[LS=\frac{cos (\pi/2 - x)}{sin(\pi/2 - x)} = \frac{sinx}{cosx} =tanx =RS\]

5 years ago
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