Help!!!
You need a 30% alcohol solution. On hand, you have a 200 mL of a 15% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution?

Question

Help!!!
You need a 30% alcohol solution. On hand, you have a 200 mL of a 15% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution?

anonymous · Answer

must be mixture day
where is @FoolForMath  when you need him?

anonymous · Answer

it is  :(haha

mertsj · Answer

200 ml + x ml = (200+x) ml
.15(200)+.80x=.30(200+x)

mertsj · Answer

Solve for x

anonymous · Answer

|dw:1337657074272:dw|
$$\frac 3{10} \times 200 = 60 ml $$