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Mathematics 16 Online
OpenStudy (anonymous):

Write an equation of a hyperbola with vertices (3,-2) and (-9,-2) and foci(7,-2) and (-13,-2) a.(x-3)^2/36-(y-2)^2/64=1. b.(x-3)^2/12-(y-2)^2/16=1 c.(x+3)^2/12-(y+2)^2/16=1 d.(x+3)^2/36-(y+2)^2/64=1

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