The number of 3 digit even number that can be formed using the 5 digits 4, 6, 7, 8, 9 .no digit being repeated?

Question

The number of  3 digit even number that can be formed using the 5 digits 4, 6, 7, 8, 9  .no digit being repeated?

anonymous · Answer

@dumbcow @ajprincess @Mertsj @blues @TuringTest @hoblos @.Sam. @shadowfiend

anonymous · Answer

the answer for this is 36 plzz solve for it.........

anonymous · Answer

choose the last digit first ==>4,6,8==>3 ways
and then it will remain only 4 digits to choose for the first two numbers
choose the first number ==> 4 ways
choose the second number ==> 3 ways (subtract the chosen first digit)
then there are 4*3*3 = 36 numbers

anonymous · Answer

thanzz

anonymous · Answer

my pleasure :))

anonymous · Answer

There are 24 digits
['467', '469', '479', '487', '489', '497', '647', '649', '679', '687', '689', '697', '749', '769', '789', '847', '849', '867', '869', '879', '897', '947', '967', '987']

anonymous · Answer

oops, I've got all odd numbers :-P http://ideone.com/WghHY There are actually 36 even numbers ['468', '476', '478', '486', '496', '498', '648', '674', '678', '684', '694', '698', '746', '748', '764', '768', '784', '786', '794', '796', '798', '846', '864', '874', '876', '894', '896', '946', '948', '964', '968', '974', '976', '978', '984', '986']