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OpenStudy (anonymous):
how to find the integration of {sin3x/(sin5x*sin2x)}
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OpenStudy (experimentx):
try, sin(3x) = sin(5x - 2x) ... then separate fractions!!
OpenStudy (experimentx):
\[ \frac{\sin 5x \; \cos 2x}{ \sin 5x \; \sin 2x} - \frac{\sin 2x \; \cos 5x}{ \sin 5x \; \sin 2x}\] that seems a lot simpler!!
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