Question

The ages of two persons differ by 16 years. If 6 years ago, the elder one be
3 times as old as the younger one, find their present ages

Answer 1

there?

Answer 2

yeah..

Answer 3

have u tried something?

Answer 4

Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
:. 3 (x - 6) = (x + 16 - 6) >> 3x -18 = x + 10 >> 2x = 28
Hence, their present ages are 14 years and 30 years.

Answer 5

thats correct. :)