A single die is rolled. What is the expected die face value, when rolling a single die?
@blockcolder @satellite73
take the average, i.e. add up the numbers and divide by 6
Is there a specific formula I could use?
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Alright, thanks @satellite73!
\[\text{if } x =\text{ the value of the roll,}\]\[\text{ }\langle x\rangle=\text {the expectation value of x,}\]\[N=\text{ is the total number of possibilities} \]\[\text{and the summation is taken over all posible x } \] \[\langle x\rangle=\sum \frac xN\] \[\langle x\rangle=\sum \frac x6=\frac {1+2+3+4+5+6}6=\frac{21}6=3.5\]
I figured it out, but thanks! :D
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