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solve the equation: (3x-2/12) - (1/6) = (1/6)
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(3x-2/12) - (1/6) = (1/6) (3x-2/12)= (2/6) 3x= 3/6 x=1/6
wait where did the -2/12 go?
I changed it into 1/6 and added it to the other side
oh. Okay
wait i think i put that wrong. the (3x-2)/12. would it still be the same. because the 3x-2 is all together.
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It would be different...Type up the actual problem?
\[((3x-2)/12) - (1/6) = (1/6)\]
((3x−2)/12)−(1/6)=(1/6) ((3x−2)/12)=2/6 3x-2=4 3x=6 x=2
Thanks (:
np
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