Question

How to solve this equation
(x^2)(lnx)-(x^2)=0

Answer 1

factor:
x^2(lnx - 1) = 0

set each factor to zero:
x^2 = 0 ---> x=0
lnx - 1 = 0 ---> x=e

Answer 2

\[x^2(lnx -1) = 0\]\[x=0 \] \[lnx=1\]
so x=0 or x=e

Answer 3

Thank dplanc and glgan 1 !!