Avril is on holidays and is hoping to sleep in every
morning for the next four weeks. Unfortunately the dog
next door may wake her earlier than she wishes. There
is a 1 in 3 chance of this happening to Avril on any
particular morning. How many days is there a chance of Avril sleeping in?

Question

Avril is on holidays and is hoping to sleep in every
morning for the next four weeks. Unfortunately the dog
next door may wake her earlier than she wishes. There
is a 1 in 3 chance of this happening to Avril on any
particular morning. How many days is there a chance of Avril sleeping in?

anonymous · Answer

She is on holidays for 28 days, so $$28\div3 \times 2$$ = the chance of her sleeping in

anonymous · Answer

thank you  @cass1 you were very helpful

anonymous · Answer

It is 18.67 days if you want an exact answer

anonymous · Answer

Well thanks for that because I didn't actually work it out @cass1