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Avril is on holidays and is hoping to sleep in every morning for the next four weeks. Unfortunately the dog next door may wake her earlier than she wishes. There is a 1 in 3 chance of this happening to Avril on any particular morning. How many days is there a chance of Avril sleeping in?
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She is on holidays for 28 days, so \[28\div3 \times 2\] = the chance of her sleeping in
thank you @cass1 you were very helpful
It is 18.67 days if you want an exact answer
Well thanks for that because I didn't actually work it out @cass1
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