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What is the sum of the arithmetic sequence 6, 14, 22 , if there are 26 terms? 2,754 2,756 2,758 2,760
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the common difference d = 8 n = 26 and a = 6 then \[s _{n} = \frac{n}{2}(2a + (n -1) d)\] substitute into the formula and evaluate... it may help to remember the formula.
First, find the 26th term. \(\Large \color{MidnightBlue}{\Rightarrow a_{n} = a_{1} + (n - 1)d }\) Then, see what the sum is. \(\Large \color{MidnightBlue}{\Rightarrow S_{n} = {n \over 2}(a_{1} + a_{l}) }\) a1 = first term aL = last term
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