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Find area of rhombus with side of length 4cm and vertex angle that measures 60 degrees. Round to nearest tenth.
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|dw:1337768873923:dw|
area of parallelogram = ab sin x a,b are sides x is angle between a and b hope you can do further,,
do you know that the diagonals inside a rhombus are bisectores,yes ?
and their halfed
yes they are
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first divide the rhombus in 2 triangles....each triangle is of 60, 30 ,30 degree....then applying tan30 in one triangle we will get the height as 4/sqrt3 the for finding the area by base *height/2 we will get the area of triangle as 8/sqrt3 the area of figure is \[16\sqrt{3}/\]
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