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Quadratic Formula 0 = x2 + 6x + 3
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a=1 b=6 c=3 \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] \[x=\frac{-6 \pm \sqrt{6^2-4(3)}}{2}\] can you take it from here?
i did that already .. i just wanna see if i get the right answer
you'll get \[x\text{ = }-3-\sqrt{6}\] \[x\text{ = }\sqrt{6}-3\]
ohhhhh okay .. i didn't get that.. thank you!
try to check, maybe its the signs incorrect
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