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MNOP will be similar to ABCD. The length of MN should be 14 and M should be located at point (1,-6) Which points will vertices N and O be located.
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from (1,-6) ,, since length of MN is 14,,N should be at (1,-6+14) or (1,8) or even (1,-6-14) i.e (1,-20) now AB is 7 units,,and BC is 3 units..due to similarity,, MN/AB= NO/BC thus NO = 6 units thus if N is at (1,8) ,,O can be at (7,8) or (-5,8) and if N is at (1,-20) ,,O can be at (7,-20) or (-5,-20) i maybe wrong,,as i am confused with similarity a bit in this case..
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