Karen is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown.
She starts with the assumption that segment DE is parallel to segment BC.

Which inequality will she use to contradict the assumption?
Answer

6:2 ≠ 7:10

6:8 ≠ 7:10

6:7 ≠ 2:7

6:2 ≠ 3:2

Question

Karen is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown.
 She starts with the assumption that segment DE is parallel to segment BC.

Which inequality will she use to contradict the assumption?
Answer
		
6:2 ≠ 7:10
		
6:8 ≠ 7:10
		
6:7 ≠ 2:7
		
6:2 ≠ 3:2

anonymous · Answer

attachment

shubhamsrg · Answer

|dw:1337649163259:dw|
for EF//BC we should have one of these :
AE/EB = AF/FC or AE/AB = AF/AC or AB/EB = AC/FC

all these come from the similar triangles property..
can you guess the ans now?

anonymous · Answer

i think it looks similar to the second option is that correct?

shubhamsrg · Answer

yes,,its the correct one! ^_^