Question

complete the square on x^2+x-6=0

Answer 1

\( x^2+x=6\)
\(x^2+x+(\frac{1}{2})^2=6+(\frac{1}{2})^2\)
\(\left(x+\frac{1}{2}\right)^2=\frac{25}{4}\)
\(x+\frac{1}{2}=\pm \sqrt{\frac{25}{4}} \)
\(x=-\frac{1}{2}\pm \frac{5}{2} \)

Answer 2

so x = -3 or 2

Answer 3

Yes.