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OpenStudy (anonymous):
solve for x: 5^(x+1) = 6^(2x) I think I have to get the bases the same, but I don't know how.
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OpenStudy (anonymous):
Take log to the both sides .....
OpenStudy (anonymous):
I don't get it can you explain @Eyad
OpenStudy (anonymous):
when u take log for the both sides ,the power will get down : (x+1) log5=(2x) log6 (x+1)/(2x)=Log6/log5...... Get it
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