Question

What are the solutions of the system?
y=x^2+4x-5
y=2x-2
A. (–3, –8) and (1, 0)
B. (–3, –8) and (–1, –4)
C. (–3, 0) and (1, –8)
D. no solution

Answer 1

How do you want to solve this?

Answer 2

put y=2x-2
in first eq

Answer 3

just substitute your x and y value into the equation.
if the value on left hand side is not same as the right hand side, then you can 'eliminate' the (x,y)

Answer 4

Or you could plug 1 in for \(x\) and see if you get 0 for \(y\). If so then \((1,0)\) is a solution.