Question

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.

Answer 1

if there are 2 real number solutions, the discriminant must be positive. So write and solve b^2-4ac>0 where b = 3, a = 1 and c = j

Answer 2

is {-1,-6} correct?

Answer 3

9-4j>0
-4j>-9
j<9/4