Question

4x^2y/2x^-1y^7

Answer 1

\[\frac{4x ^{2y}}{2x ^{-y^7}}\]

Answer 2

Is that the problem?

Answer 3

yes :)

Answer 4

In that case, divide 4 by 2 and subtract the exponents since both bases are x:
\[2x ^{y^7+2y}\]

Answer 5

thank you :)

Answer 6

yw