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Mathematics 16 Online
OpenStudy (anonymous):

The center of the circle with equation (x - 3)2 + (y + 2)2 = 4 has coordinates ___.

OpenStudy (anonymous):

6,-4 I think

OpenStudy (anonymous):

oops those are suppose to be ^2 not 2

OpenStudy (anonymous):

3,-2 is your center i'll check

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

yup it is 3,-2 :)

OpenStudy (anonymous):

oh and it is (x-3)^2+(y+2)^2 = 4 not (x - 3)2 + (y + 2)2 = 4

OpenStudy (anonymous):

ok

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