The six faces of a cubical box each measure 74.9 cm by 74.9 cm and the faces are numbered such that faces 1 and 6 are opposite each other, as are faces 2 and 5, and faces 3 and 4. the flux through each face is:

Question

The six faces of a cubical box each measure 74.9 cm by 74.9 cm and the faces are numbered such that faces 1 and 6 are opposite each other, as are faces 2 and 5, and faces 3 and 4.  the flux through each face is:

anonymous · Answer

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anonymous · Answer

Find the net charge inside the cube.

So I used Gauss's law and summed up all the flux, ten multiplied by the permitivity of free space.  My order of magnitude is right, but my answer is wrong.  Was it wrong to sum them up by their values without regard to the surfaces?  Also, I didn't use the area of the sides of the cube at all in the equation.

anonymous · Answer

I think


sum of flux= q/ epsilon not