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find all real solutions 3x2 + 12x + 4 = 0
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factor then solve
(3x+4)(x+1)=0?
since u can not factor then just use the quardratic formula and canel the not real numbers
http://www.regentsprep.org/Regents/math/algtrig/ATE3/quadformula.htm that is the quadratic formula
use it and substutite a=3 b=12 and c=4
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did u get it?
If you apply the quadratic formula, you will get \[ \left\{x=\frac{2}{3} \left(-3-\sqrt{6}\right),\quad x=\frac{2}{3} \left(\sqrt{6}-3\right)\right\} \]
I didn't get it yet
I got one = -.37 and the other as -3.63
that is right
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