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Inverse Trigonometric Function problem. Please Help:)
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What's the function?
I want to see How \[\sin^{-1} \sin \theta=-\pi-\theta\] For \[\theta \in [-3\pi/2,-\pi/2].\]
@Mertsj Please help:)
@Callisto & @lalaly please help:)
u give me only a hint:) Rest I will do!
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ya I kno that but I want a proof for my question:(
Here's your hint \[ \sin(-\theta) = -\sin\theta\] \[ \sin ( \pi + \theta) = -\sin \theta \]
@apoorvk I have got the solution for this. Please u also see :)
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