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Mathematics 9 Online
OpenStudy (anonymous):

Solve 0 = 16t^2 + 233t + 0 for t.

OpenStudy (anonymous):

use the quadratic formual

OpenStudy (anonymous):

do you know what that is?

OpenStudy (anonymous):

Yes but is it just the same thing considering its velocity question?

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

alright well thanks then I wasn't sure

OpenStudy (lalaly):

\[16t^2+233t=0\]\[t(16t+233)=0\]\[t=0,\frac{-233}{16}\]

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