What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)
A. -51
B. -51
x - 3
C. -17
x
D. -17
x - 3

Question

What is the remainder of (x^3 – 6x – 9x + 3) ÷ (x - 3)
A. -51 	
	B.           -51   
                   x - 3 	
	C.           -17   
                     x 	
	D.           -17   
                   x - 3

jhonyy9 · Answer

before all i think that the second term is 6x^2 ,or not is ?
so than the remainder will be :

x^3 -6x^2 -9x +3 : x-3 =x^2 -9x -36
x^3 +3x^2
----------
 0    -9x^2 -9x 
       -9x^2 +27x
      ------------
           0    -36x +3
                 -36x +108
                -----------
                    0    -105

- so hence the remainder is -105

anonymous · Answer

i got D

anonymous · Answer

answer ?

jhonyy9 · Answer

so the second term not is -6x^2 ?

anonymous · Answer

wait , yeah ..

jhonyy9 · Answer

please write new correct your exersice