Solve for x in the proportion x+1 over 8 and 2x - 5 over 2

Question

parthkohli · Answer

$\Large \color{MidnightBlue}{\Rightarrow {x + 1 \over 8} = {2x - 5 \over 2} }$

Let's now cross multiply to eliminate the fraction.

$\Large \color{MidnightBlue}{\Rightarrow 2(x + 1) = 8(2x - 5) }$

$\Large \color{MidnightBlue}{\Rightarrow 2x + 2 = 16x - 40 }$

$\Large \color{MidnightBlue}{\Rightarrow 2x + 42 = 16x }$

$\Large \color{MidnightBlue}{\Rightarrow 14x = 42 }$

$\Large \color{MidnightBlue}{\Rightarrow x = 3 }$

parthkohli · Answer

@Brad1996 Do you know why we cross multiply?

anonymous · Answer

i forgot the reason i just know ur suppose to

anonymous · Answer

@ParthKohli  : suppose u multiple equation by multiple product of each side dem . 
i mean for this ex suppose u multiple equation by (2*8)
u cancel num and dem and it;s just like u cross multiple .

parthkohli · Answer

Of course @Roya I know that. I was asking Brad.

anonymous · Answer

@ParthKohli  , sri dear .

parthkohli · Answer

He he no need