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(-12+6i)/3
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-4 + 2 i
Divide as normal term by term: = -12/ 3 + 6i/ 3 = ....
the book is giving me an answer of 2+4i why is that?
It's typo!
cool thanks
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Operate with a constant normally, pretend "i" as x !
can you please show me the steps
Here they are ;) -12/ 3 = ... + 6i/ 3 = ...
thanks more of a visual learner
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