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pls help solve these!! 1. y=7/(2x+48) 2. y=1/(x-2) -3
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Are you supposed to solve for x?
what are we suppose to solve for?
x
y=7/(2x/+48) , why is there a dividion sign iside the parenthese?
there isnt one... typo my bad lol i fixed it
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y=7/(2x+48) y(2x+48) = 7 2xy + 48y = 7 2xy = 7 - 48y x = (7 - 48y)/(2y) So the solution is \[\Large x = \frac{7-48y}{2y}\]
what are the excluded values?
y cant be zero (to avoid division by zero)
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