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A polygon has 11 sides. What is the sum of the measure of the interior angles of the polygon? 1800° 1620° 1440° 1980°
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no it's not 1980
nope. The equation is 180 *(n-2) where n is the number of sides. so, 180 * 9
Place a point inside the polygon, and draw lines to each corner. You will have 11 triangles, eacjh of 180 degrees. Subtract the central angle.
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