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x^3+27=0
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What are you supposed to do with it?
solve for x
(x+3)(x^2-3x+9)=0
i was thinking the answer was \[\pm3\sqrt{3}i\] but idk
one answer is -3 Use the quadratic formula to solve x^2-3x+9=0
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who where did you get (x+3)(x^2-3x+9)=0 from???
I factored x^3+27. It is the sum of 2 cubes
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]
oh ok cool i didnt know you could do that!
You must have missed school on the factoring days.
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haha this is our summer school homework for calculus so i dont know how to do some of it and/or the things in the packet, i did a long time ago
Well, you're smart. You'll easily pick it up again.
ha thanks!
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