An object is launched from ground level with an initial velocity of 400 feet per second. To the nearest tenth of a second, how long does it take the object to reach a height of 650 feet?

Question

anonymous · Answer

If we are not taking gravity into effect - and if the object is launched directly upwards, it's a matter of

650 (feet) / 400 (feet per second) = how many seconds it takes.

anonymous · Answer

Thank you!

anonymous · Answer

use the formular
s = ut + (1/2) at^2

anonymous · Answer

thankyou!

anonymous · Answer

If the question's been answered, please close the question when you've got the chance!