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Mathematics 19 Online
OpenStudy (anonymous):

Solve for y1

OpenStudy (anonymous):

\[xy _{1}+xy _{1}y^2-3=5y _{1}+xy\] solve for \[y _{1}\]

sam (.sam.):

xy1+xy1y2−3=5y1+xy xy1+xy1y2-5y1−3=xy , factor y1 y1(x+xy2-5)=xy+3 y1=(xy+3)/(x+xy2-5)

OpenStudy (anonymous):

thanks!

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