Question

How many different pairings (2 teams playing each other) are possible for the first round of the 64 teams in the NCAA Basketball Tournament? (without seeding)

Answer 1

\[64C2=\frac{64!}{2!(64-2)!}=\]

Answer 2

Forgive me. Kropot is correct. We should be using combinations and not permutations.

Answer 3

Answer is:\[\frac{64\times 63}{2}\]