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(x+7)^(2/3) = 9 x can equal ?
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\[(x+7)^\frac23=9\]
\[\Huge(x+7)^\frac23=9\] \[\Huge(x+7)=9^\frac32\] \[\Huge x=9^\frac32-7\]
x is supposed to have 2 possible answers and somehow i got 20...
i dont know how to show it becasue im bad with the equation maker thing :(
Is the problem expression the following?\[(x+7)^{2/3}=9 x \]
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\[\Huge(x+7)^\frac23=9\] \[\Huge(x+7)^2=9^{3}\] \[\Huge(x^2+14x+49)=9^{3}\] \[\Huge(x^2+14x-680)=0\] (x+34)(x-20)=0
2 solutions there
ok , thanks so -34 and 20?
yes
thanks :D
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welcome ;)
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