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Find the roots of x^3+2x^2-5x-6=0
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just factor (x-2)*(x+3)*(x+1)=0 can you solve that?
Would you do the separatly? I do not get how that works.
once you factor you can set each individual ( ) to 0 ( )=0 you should get 3 roots
x-2=0 x+3=0 x+1= 0 solve each one
So would it be 2,-3,-1?
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yes :)
if you have a graphing calculator you can graph it and find where x intersect 0
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