Question

what term is under the radical sign when solving for
5x^2 - 2x - 2 = 0

Answer 1

\[x=[-(-2) \pm \sqrt{(-2)^2-4(5)(-2)}]/2(5)\]\[x=[2 \pm \sqrt{14}]/10\]
so the term is 14.

Answer 2

the trem is 44 thx though