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determine the antiderivative of (x^2) sqrt (25-x^2) dx show steps plz
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\[\int\limits x^2 \sqrt{25-x^2}dx\]?
Trig sub is what you need
x=5sin(u) dx=5cos(u)du
x/5=sinu u=sin^(-1)x/5
\[25\int\limits 25 \sin ^2(u) \cos ^2(u) \, du\]
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oh man long step ahead
@Sam I am trying to teach myself integration. How could you tell you needed a trig substitution ?
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