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Solve 4^3x=64^2x-6 without using logs
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Can use natural log?
Nevermind there's a trick
\[\Huge 2^{2(3x)}=2^{6(2x-6)}\] \[\Huge 2(3x)=6(2x-6) \] Solve
Make the base same and , you can bring down the exponents
6x= 12x + 36 -6x=36 x= -6?
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Never mind.
very close, 2(3x)=6(2x−6) 6x=12x-36 -6x=-36 x=6
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